(x^2-9)/(x+4)(x+3)=0

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Solution for (x^2-9)/(x+4)(x+3)=0 equation: 


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

((x^2-9)/(x+4))*(x+3) = 0

((x^2-9)*(x+3))/(x+4) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x^2-9 )

1*x^2 = 9 // : 1

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x in { -3, 3, -3 }

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